Exercise
In which polynomial ring
is X3 + X + 1 reducible?
Z/2Z[X].
Z/11Z[X].
Q[X].
No, the polynomial has no zeros and hence no linear factors
and hence no quadratic factors either.
Yes, 2 is a zero.
No. Substitute a rational number
r/
s with
r
and
s relatively prime, clear denominators and investigate
divisibility of the resulting identity by
r and
s.
You should find that the only possibilities are 1 and -1. Substitute
them to exclude these possibilities.
(see also the
Exercises).