Exercise
The inverse of
X
+ 1 in
Q
[
X
]/(
X
2
)
is
X
- 1.
is 1 -
X
.
does not exist.
No, the product (
X
+ 1)(
X
- 1) modulo
X
2
is not 1.
Yes, this is correct.
No,
X
+ 1 does have an inverse as gcd(
X
+1,X
2
) = 1.