Let f = X2 + X + 1 be a polynomial in R = Z/2Z[X]. Then f is irreducible. The field K = R/(f) has 4 elements:
The multiplication table of the set K* of invertible elements (in the case of a field this coincides with the set of nonzero elements) is as follows:
| 1 | a | a + 1 | |
| 1 | 1 | a | a + 1 |
| a | a | a + 1 | 1 |
| a + 1 | a + 1 | 1 | a |