0,
is the ideal (gcd(m,n)).
To see this, let a and b be integers such that am + bn = gcd(m,n) (they can be found by menas of the extended Euclidean algorithm). This equality shows that gcd(m,n), and therefore every multiple of it, belongs to the ideal generated by m and n. This shows that the ideal (gcd(m,n)) is contained in the ideal (m) + (n).
On the other hand, every element cm + dn of the sum ideal (m) + (n)
is a multiple of gcd(m,n), since both m and n
are multiples of this gcd.
0.
If m and n divide d,
then the sum of the ideals
(m) and (n) of Z/dZ
is the ideal (gcd(m,n)).
0.
0.