Remarks
-
In
a previous proposition,
we saw that, for any power r = pb of p,
the subset {x
F | xr = x}
is a subfield of F.
Apparently,
- for r = q, the subfield coincides with F;
- the subfield only depends on the value of b mod a,
where q = pa.
-
Note that xq - 1 = 1 for nonzero x in F.