Let K be a subfield of L and let
f
K[X] be an irreducible polynomial. If
x, y are two roots of f in L, then there is
an isomorphism h : K(x) -> K(y)
with h(x) = y.
On the other hand, each isomorphism K(x) - > K(y) which fixes K elementwise, is determined by the image of x. Hence we can determine automorphism groups of finite fields.
Let p be a prime number and q = pa a power of p. If K is a finite field of order q, then Aut(K) is a cyclic group of order a generated by the map x -> xp.